20 September 2010, 22:40 | #1 |
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cd32 rgb scart connection
I want to try to add a scart rgb connector to my cd32. I have red a post about connecting a scart cable to the tp9.
This involves soldering resisters to get the right signals. I also came across another post. In this post the scart cable is directly connected to the Sony CTA1145M chip. (see picture 1) Is this possible without using any additional resisters? In this post pin 11, 21, 22, 23 of the sony chip (see picture 2) are used for r,g,b and c-sync. Do I have to make a ground connection ?. If yes, where to make the ground connection ? THanks, Ben |
20 September 2010, 23:03 | #2 |
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pin 24? see datasheet for CXA1145 - You need 2 resistors and 1 condenser for each output pin (8 resistors 75 ohm and 4 condensers - 470uF on datasheet example)
http://www.alldatasheet.com/datashee.../CXA1145M.html |
21 September 2010, 00:08 | #3 |
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I did this once, soldered wires to TP9 and I read that if your TV does not have an amplifier on the SCART inputs then the screen comes out at half brightness because these signals were not designed to drive a SCART cable.
Worked for me though. |
22 September 2010, 19:32 | #4 |
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Thank you for your reply. I am going to try to make a scart connection on the tp9 port.
As I understand on the red, green, blue and sync connection I have to add a resistor of 47 Ohm to get the correct scart output. tp9-> scart: Blue -> 47 ohm -> scart pin 7 Green -> 47 ohm -> scart pin 11 Red -> 47 ohm -> scart pin 15 Sync -> 47 ohm -> scart pin 20 RGB status: 12v -> 150 Ohm (to get output of 1,5v) -> scart pin 16 There is also a connection mentioned to scart pin 8. This will allow your tv to automatically choose the scart channel. It has to be connected by 12v with a 1kOhm resistor. Why use a 1kOhm resistor. I measured the scart output of my dvd player and pin 8 has a 1v current. To get a 1v current on the 12v connection a resister of 157 Ohm has to be sufficient. Calculation: 12v -> 1,5v U=IxR (ohms law) 12 - 1,5 = 10,5v 10,5 = 0,07 x resistor resistor = 10,5 / 0,07 = 150 Ohm 12v -> 1,0v U=IxR 12 - 1,0 = 11 11 = 0,07 x resistor resistor = 11 / 0,07 = 157 Ohm Is this the way to make a scart connection from the tp9 port. Greeting, Ben |
23 September 2010, 00:44 | #5 | |
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Quote:
I think you have to try it. If the picture is too dark then you'll have to use an amplifying circuit. BTW in your calculations for SCART PIN 16 & 8 you do not take into consideration the resistance of the electronics in your TV (usually rated at 75 ohm) so you need a potential divider circuit to calculate the resistances required to lower 12v or 5v to the required levels. |
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23 September 2010, 09:17 | #6 | ||
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Quote:
Quote:
https://secure.wikimedia.org/wikipedia/en/wiki/SCART Pin 16 - Fast Blanking 5V as source will be much better, use RED LED as "Zener diode" (this is FAST signal so impedance is 75 ohms - or it can be TTL - at the beginning it was TTL level signal to overlay ext RGB on TV) Pin 8 - Function Switching 12V line by 1k resistor is ok (this is SLOW signal and it is measured on 10kohm impedance then 1kohm impedance is enough) So best - use high bandwidth 3 channel video buffer (eg TSH345) to the TP9 or use CXA1145 avoid direct connection from TP9 |
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23 September 2010, 14:29 | #7 | ||
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Quote:
Not sure what to do now. Maybe I try a direct connection to the CXA1145 for the red, green, blue and sync. connect Pin 8 to 12V line by 1k Ohm resistor. Quote:
-connect Pin 16 to 5v line by this RED LED (Zener diode) or -connect pin 16 to 12v line by 150 Ohm resistor Is this correct? Sorry for asking this one more time, I just want to make sure I understand this correctly. Greetings, Ben |
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23 September 2010, 16:47 | #8 | |
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This is perfect.
Quote:
Pin 16 is "TTL" level pin with impedance approx. 75 ohms. It is more safe to use 5V than 12V - Pin 16 expect 1 - 3V. then You can connect to line 5V red (green, yellow - ie any color) LED that have voltage drop (diode begin conducting) approx 1.5 - 3V - typical green or new hi bright red LED are approx 2.1 - 2.2V. To limit current that flow trough LED You need resistor - 150 ohm should be ok. so i will try to make ASCII drawings LED +5V o-----|_R_|---*---|>|----| GND ...........................| ...........................*-----------o connected to the Pin16 dots used as a space - In this point (*) voltage level should be approx. 1 - 3V instead of LED, 3 silicone diodes in series like 1n4148/1n400x can be used but LED give You some visual information that circuit works. |
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23 September 2010, 19:35 | #9 | |
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Hope I can make it work, thanks again. Greetings, Ben |
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