hex2ascii in asm

redblade · 26 June 2005, 10:08

hi does any one one have a asm routine where i can feed the hex value in a data reg ie d0, and the output in a0, and it converts it to say from

d0 = !655,

and then down in the buffer.

buffer: dc.b 0,0,0,0

after the routine it gets updated to

buffer: dc.b '655',0 ;after being converted back to ascii?

sorry had a quick look on aminet and i couldn't find a routine.

Wepl · 27 June 2005, 17:30

Code:

move.l #655,d0
lea    buffer,a0

divu   #100,d0
add.b  #"0",d0
move.b d0,(a0)+
clr.w  d0
swap   d0
divu   #10,d0
add.b  #"0",d0
move.b d0,(a0)+
swap   d0
add.b  #"0",d0
move.b d0,(a0)+

redblade · 28 June 2005, 00:34

cheers matey

.

just about had problems there with the:
add.b #"0",d0

but I realized you were just converting it back to the Ascii numerical value.

, so thanks.

would code still be the same if it was d0=$299 not d0=!665?

Codetapper · 28 June 2005, 02:49

The above code will work for any number under 999. It you need it to go higher, just start off by dividing by 1000, then 100, 10 etc. I don't know what !665 means either, what is the exclamation mark for? $ signifies hexadecimal, what on earth is ! for?

alexh · 28 June 2005, 08:33

I think he meant to say "can I use:"

Code:

move.l #$28F,d0

instead of:

Code:

move.l #655,d0

which of course he can.

You'll note that $299 is of course 665 and not 655 as in Wepl's code

Wepl · 28 June 2005, 09:07

Quote:

Originally Posted by Codetapper

The above code will work for any number under 999. It you need it to go higher, just start off by dividing by 1000, then 100, 10 etc. I don't know what !665 means either, what is the exclamation mark for? $ signifies hexadecimal, what on earth is ! for?

!665 is decimal notation, for example used in Action Replay
the routine will work for any number below 1000 not 999

for much bigger numbers it will make sense to write a loop maybe...

redblade · 30 June 2005, 10:56

yeah sorry about that, after posting that msg, i thought for a while and realised that the routine was still going to work.

so problem answered.

Thanks people

27 June 2005, 17:30	#2
Wepl Moderator Join Date: Nov 2001 Location: Germany Posts: 866	Code: move.l #655,d0 lea buffer,a0 divu #100,d0 add.b #"0",d0 move.b d0,(a0)+ clr.w d0 swap d0 divu #10,d0 add.b #"0",d0 move.b d0,(a0)+ swap d0 add.b #"0",d0 move.b d0,(a0)+

28 June 2005, 08:33	#5
alexh Thalion Webshrine Join Date: Jan 2004 Location: Oxford Posts: 14,337	I think he meant to say "can I use:" Code: move.l #$28F,d0 instead of: Code: move.l #655,d0 which of course he can. You'll note that $299 is of course 665 and not 655 as in Wepl's code

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26 June 2005, 10:08	#1
redblade Zone Friend Join Date: Mar 2004 Location: Middle Earth Age: 40 Posts: 2,127	hex2ascii in asm hi does any one one have a asm routine where i can feed the hex value in a data reg ie d0, and the output in a0, and it converts it to say from d0 = !655, and then down in the buffer. buffer: dc.b 0,0,0,0 after the routine it gets updated to buffer: dc.b '655',0 ;after being converted back to ascii? sorry had a quick look on aminet and i couldn't find a routine.

28 June 2005, 00:34	#3
redblade Zone Friend Join Date: Mar 2004 Location: Middle Earth Age: 40 Posts: 2,127	cheers matey . just about had problems there with the: add.b #"0",d0 but I realized you were just converting it back to the Ascii numerical value. , so thanks. would code still be the same if it was d0=$299 not d0=!665?

28 June 2005, 02:49	#4
Codetapper 2 contact me: email only! Join Date: May 2001 Location: Auckland / New Zealand Posts: 3,182	The above code will work for any number under 999. It you need it to go higher, just start off by dividing by 1000, then 100, 10 etc. I don't know what !665 means either, what is the exclamation mark for? $ signifies hexadecimal, what on earth is ! for?

30 June 2005, 10:56	#7
redblade Zone Friend Join Date: Mar 2004 Location: Middle Earth Age: 40 Posts: 2,127	yeah sorry about that, after posting that msg, i thought for a while and realised that the routine was still going to work. so problem answered. Thanks people

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