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04 February 2023, 15:45
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#1 |
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Zone Friend
Join Date: May 2006
Location: France
Posts: 1,801
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Bug in WinUAE debugger or in me?
Version 64bit 4.10.0
WinUAE debugger 4.10.0 2022 12 18 64bit? I was expecting the code to go to $c65e and not $c666 it is a bug right? >m 1a16 00001A16 7F00 0700 42B9 0000 6B24 4239 0000 1E72 ....B...k$B9...r >d c650 0000c650 c482 and.l d2,d2 0000c652 4e75 rts == $000015c2 0000c654 0c39 007f 0000 1a16 cmp.b #$7f,$00001a16 [7f] 0000c65c 6608 bne.b #$08 == $0000c666 (F) 0000c65e 08f9 0005 0000 c482 bset.b #$0005,$0000c482 [00] 0000c666 0c39 0077 0000 1a16 cmp.b #$77,$00001a16 [7f] |
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04 February 2023, 16:36
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#2 |
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Registered User
Join Date: Jun 2016
Location: europe
Posts: 1,039
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Use HH <number_of_instructions> to get full info on cpu''s what&why.
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04 February 2023, 17:02
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#3 |
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Defendit numerus
Join Date: Mar 2017
Location: Crossing the Rubicon
Age: 53
Posts: 4,474
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WinUAE (when disassemble) uses the instantaneous value of the flags (check the SR value and you will see that you have the 'right' Z).
It can't know that in advance except by emulating the instruction stream! Sure, it's easy for you to see 'by eye', but it can't know if any code modifies the contents of the cell before it gets to that point in the code. |
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06 February 2023, 07:46
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#4 |
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Zone Friend
Join Date: May 2006
Location: France
Posts: 1,801
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The executed code is c566
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06 February 2023, 09:45
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#5 | |
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Defendit numerus
Join Date: Mar 2017
Location: Crossing the Rubicon
Age: 53
Posts: 4,474
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Quote:
This simply means that somewhere else in the code (an IRQ?) that cell (1A16) has been modified. It wouldn't be so strange, it's basically the function of that piece of code since it looks like a switch construct. But if you want to remove any doubts put a breakpoint at C65E or C666, then check the offending cell. If instead the cell contains 7F then it's a bug 
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