C code prob

[thor]

For the endian check you have to do:
unsigned short endian_test = 0x0001;

if (*(unsigned char*)&endian_test) == 1)
/* little endian */
else
/* big endian */


Explanation:
- with the address operator & you get the address where endian_test is stored.
- with (char*) you cast it to a pointer to chars
- with indirection operator * you get the char (since you converted it to char pointer) at that memory address
- in little endian it is stored in memory as 0x0100, in big endian 0x0001 (in bold the result of the expression)

Since you didn't initialize your variable, the result was undefined and therefore didn't work

[eLowar]

Nice one, I can't really help with endian-ness problems, because I usually don't have to deal with them (fortunately).

@Jherek: There's still a little conversion error somewhere (possibly just a forgotten conversion). See my post above for an example and you should probably find it with ease.

[Jherek Carnelia]

Thanks for the look.

In my haste I overlooked the fact that the second part of the code that converts the buffer contents into strings of registers and values and into display lines and pixel positions relies on the buffer being stored as an Amiga.

Needs more work. But then it is a good exercise - and that's what I'm looking for!