Quote:
Originally Posted by Don_Adan
Sorry you are wrong, if you use move.b #64,$DFF0A8, you have $4040 in $dff0a8 register for 68000 to 68030, but for 68040/68060 you have $4000 only (if $dff0A8 was null before).
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If you use a byte write, I guess you have to write to $dff0a9 to set bits 6-0, but you're saying that on a 68000, performing "move.b #$40, $dff0a8" will actually be the same as performing "move.w #$4040, $dff0a8" ???