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Old 21 September 2015, 00:56   #9
Leffmann
 
Join Date: Jul 2008
Location: Sweden
Posts: 2,265
The vector field that defines the motion is the sum of a horizontal displacement of the columns, a vertical displacement of the rows, and a horizontal and vertical skewing.

The center of motion in this case will be where the displacements net zero, plus half the grid size, but you forget that you have a wider screen, so if you change the terms -x and x into -(x-3) and x-3, or maybe -(x-4) and x-4, for your source coordinates, then you should get the center of motion close to the center of your screen.
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