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meega · 14 May 2010, 22:08

I think I prefer the already established 14-bit approach (8-bit "high" + 6-bit "low" for each of left and right, works because you have 4x 8-bit channels available).

14 May 2010, 22:08	#2
meega Registered User Join Date: Dec 2007 Location: Oooh what a feeling yeaaah dancing on the ceiling Posts: 314	I think I prefer the already established 14-bit approach (8-bit "high" + 6-bit "low" for each of left and right, works because you have 4x 8-bit channels available).