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Old 07 July 2019, 19:00   #1156
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Join Date: Oct 2017
Location: Sunderland, England
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Originally Posted by Don_Adan View Post
In this routine? Only byte is modified. Or Im blind.
Originally Posted by ross View Post
No, D1 can be any value, all preceding bit in .b position are destroyed.
Why do you think it should be 0?
My bad - you are as always right... ... for some reason I misinterpreted the roxr.b in that it would rotate the bits back in to the msb of the byte.

The actual first run always produces 0 of the correct before it is pushed onto the LUT.

I'll get my coat.
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