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Old 07 July 2019, 19:00   #1156
mcgeezer
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Join Date: Oct 2017
Location: Sunderland, England
Posts: 1,314
Quote:
Originally Posted by Don_Adan View Post
In this routine? Only byte is modified. Or Im blind.
Quote:
Originally Posted by ross View Post
No, D1 can be any value, all preceding bit in .b position are destroyed.
Why do you think it should be 0?
My bad - you are as always right... ... for some reason I misinterpreted the roxr.b in that it would rotate the bits back in to the msb of the byte.

The actual first run always produces 0 of the correct before it is pushed onto the LUT.

I'll get my coat.
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