Quote:
Originally Posted by StingRay
That's because of the byte write, value for the volume has nothing to do with it.
Edit: too slow again.  |
Sorry you are wrong, if you use move.b #64,$DFF0A8, you have $4040 in $dff0a8 register for 68000 to 68030, but for 68040/68060 you have $4000 only (if $dff0A8 was null before), and yes only 7 bits are used.