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Old 20 October 2016, 20:07   #35
pandy71
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Join Date: Jun 2010
Location: PL
Posts: 1,532
Quote:
Originally Posted by thellier View Post
@Thorham

So: " the total is 64+64 values values possibles for each R, G or B channels
So 128*128*128 = 2097152 = 2 mega pixels"
Isn't better to define problem that 2 LSB are from CLUT and 6 MSB are dynamically changed by HAM.
So going with your approach it will be like 2+2+2=6 bits and 6+6+6=18 ; 6+18 =24.
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