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Old 02 September 2016, 21:32   #10
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Join Date: Sep 2011
Location: Cardiff, UK
Posts: 1,124
Thanks for trying to explain, but I'm still not clear on this:

To make things simple, a data of 1 with a volume of 64 is the same as a data of 64 with a volume of 1 ; therefore a data of 32 with a volume of 1 would be 1/2, and so on down to 1/64.
Maybe if it were written out in binary, with the high and low bits?
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